[tex]\bf (\stackrel{a}{7}~~,~~\stackrel{b}{6})\impliedby \textit{let's find the hypotenuse first}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{7^2+6^2}\implies c=\sqrt{49+36}\implies \boxed{c=\sqrt{85}}
\\\\\\
sec(\theta)=\cfrac{hypotenuse}{adjacent}\qquad \qquad sec(\theta )=\cfrac{\sqrt{85}}{7}[/tex]
