What is the constant of proportionality for the relationship shown in the table
A.1/2
B.2
C.4
D.8
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Answer:
Option A
[tex]1/2[/tex]
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex] or [tex]y=kx[/tex]
In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin
so
For [tex]x=2, y=1[/tex]
[tex]k=y/x=1/2[/tex]
For [tex]x=4, y=2[/tex]
[tex]k=2/4=1/2[/tex]
For [tex]x=6, y=3[/tex]
[tex]k=3/6=1/2[/tex]
For [tex]x=8, y=4[/tex]
[tex]k=4/8=1/2[/tex]
Answer:
Option A is correct
[tex]\frac{1}{2}[/tex]
Step-by-step explanation:
Direct proportionality states:
if [tex]y \propto x[/tex]
then, the equation is in the form of:
[tex]y = kx[/tex] ......[1] where, k is the constant of proportionality.
As per the statement:
Consider any points from the given table:
Let (x, y) = (4, 2)
Substitute these points in [1] we have;
[tex]2 = 4k[/tex]
Divide both sides by 4 we have;
[tex]\frac{1}{2} = k[/tex]
or
[tex]k=\frac{1}{2}[/tex]
Therefore, the constant of proportionality for the relationship is, [tex]\frac{1}{2}[/tex]