A jeweler has five rings, each weighing 18 grams, made of an alloy of 10% silver and 90% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 45 %. How much silver should he add?

Respuesta :

five rings, 18 grams each, so the total is 18*5=90 grams
suppose he adds x grams of silver, the total weight will be 90+x grams
out of these 90+x grams, 45% of it is gold, so the amount of gold is 0.45(90+x)
this amount of gold is the same as the old amount, which is 90% of 90=81, because no gold was added.
so we have an equation: 0.45(90+x)=81
solve: 90+x=81÷0.45=180
x=90
He needs to add 90 grams of silver.

The silver that should be added is 90 grams.

Given that,

  • There is 5 grams, each weighted for 18 grams make it of 10% silver and 90% gold.
  • The gold content to 45%.
  • Let us assume the silver grams be x so the total should be [tex]18\times5[/tex] = 90 and, the total weight should be 90 + x.

Based on the above information, the calculation is as follows:

0.45(90+x) = 90% of 90

40.5 + 0.45x = 81

x = 90 grams

Therefore, we can conclude that the silver that should be added is 90 grams.

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