Following are the solution to the given rational number:
Given:
[tex]\bold{\sqrt{35}+ \sqrt{5}=\sqrt{45}}\\\\\bold{3\sqrt{16}+3\sqrt{16}= 6\sqrt{16}}\\\\\bold{\sqrt{12}+0.5=1 }\\\\\bold{\sqrt{10}+(- \sqrt{10})=0}[/tex]
To find:
Solve the value.
Solution:
Solving the given choices:
For the first choice
[tex]\bold{\sqrt{35}+ \sqrt{5} \neq \sqrt{45}}\\\\[/tex] it is wrong.
For the second choice:
[tex]\bold{3\sqrt{16}+3\sqrt{16}= 6\sqrt{16}}\\\\[/tex] that is correct because it is rational numbers are closed under addition.
For the third choice:
[tex]\bold{\sqrt{12}+0.5=1 }\\\\[/tex] it is wrong.
For the fourth choice:
[tex]\bold{\sqrt{10}+(- \sqrt{10})=\sqrt{10}- \sqrt{10}=0}[/tex] solve value is correct but not rational numbers are closed under addition.
Therefore, the answer is "second choice".
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brainly.com/question/11398695
