1.The slope of a line is -4, and the y-intercept is -3. What is the equation of the line written in slope-intercept form?
y = -4x - 3
y = -4x + 3
y = 4x - 3

2.The graph of a line passes through the two points (-2, 1) and (2, 1). What is the equation of the line written in general form?
y - 1 = 0
x - y + 1 = 0
x + y - 1= 0

3.The slope of a line is -1/3, and the y-intercept is 10/3. What is the equation of the line written in general form?
10x + 3y - 1 = 0
x + 3y + 10 = 0
x + 3y - 10 = 0

4.Write the equation of the line that has an x-intercept of -3 and passes through the point (-3, 7).

x = -3
y = -3
y = 7

Respuesta :

In y = mx + b form, the slope is in the m position and the y int is in the b position

1. slope of -4....y int of -3
    y = -4x - 3 <==

2. (-2,1)(2,1)...u have the same y coordinates..this means u have a horizontal line with a slope of 0. 
     y = 1......y - 1 = 0 <===

3. slope = -1/3 and y int = 10/3...
    y = -1/3x + 10/3....add 1/3 to both sides
    1/3x + y = 10/3...multiply everything by 3
     x + 3y = 10
     x + 3y - 10 = 0 <==

4. (-3,7)...and if the x int is -3, then its points are (-3,y)...meaning u have points where the x coordinates are the same...meaning vertical lines...ur answer is x = -3
ANSWER TO QUESTION 1

The equation of a line in slope intercept form is given by the formula,

[tex]y = mx + c[/tex]
where
[tex]m[/tex]
is the slope of the straight line and
[tex]c[/tex]
is the y-value of the y-intercept.

It was given in the question that, the slope is -4.

Thus,

[tex]m = - 4[/tex]

It was also given that the y-intercept is -3.

Thus,

[tex]c = - 3[/tex]

Therefore the equation is

[tex]y = - 4x + - 3[/tex]

This gives us,

[tex]y = - 4x - 3[/tex]

The correct answer is A

ANSWER TO QUESTION 2

We were given that the equation passes through the two points (-2,1) and (2,1).

We can see from the points that the y-values are constant. This means that the line is parallel to the x-axis

Therefore the equation is given by

[tex]y=y_1[/tex]
where
[tex]y_1[/tex]
is the constant y-value.

Thus, the equation is,

[tex]y = 1[/tex]

or we write in general form to get,

[tex]y - 1 = 0[/tex]

The correct answer is A.

We could have also decided to find the slope,

[tex]m = \frac{ 1 - 1}{2 - - 2} = \frac{0}{4} = 0[/tex]

using any point, say
[tex](2,1)[/tex]

we plug into the point slope form formula to get,

[tex]y - 1 = 0(x - - 2)[/tex]

This gives us
[tex]y - 1 = 0[/tex]

ANSWER TO QUESTION 3

The equation of a straight line in the slope intercept form is
[tex]y = mx + c[/tex]

where m is the slope and c is the y-intercept.

Thus,

[tex]m = - \frac{1}{3} [/tex]
and
[tex]c = \frac{10}{3} [/tex]

We substitute in to the formula to obtain,

[tex]y = - \frac{1}{3} x + \frac{10}{3} [/tex]

we multiply through by 3 to obtain,

[tex]3y = - x + 10[/tex]

We rewrite in general form by equating everything to zero.

Thus,

[tex]3y + x - 10 = 0[/tex]

Or

[tex]x + 3y - 10 = 0[/tex]

The correct answer is option D.

ANSWER TO QUESTION 4

We want to write the equation of the line that has an x-intercept of -3 and passes through the point (-3, 7).

This implies that the line passes through the points,

[tex](-3,0) \: and \: (-3,7)[/tex]

We find the slope as follows,

[tex]m = \frac{7 - 0}{ - 3 - - 3} = \frac{7 - 0}{ - 3 + 3} [/tex]

This implies that,
[tex] m= \frac{7}{0} [/tex]
The slope is undefined. This means the line is parallel to the y-axis.

The equation of a line that has an undefined slope or parallel to the y-axis is given by

[tex]x=x_1[/tex]

where
[tex]x_1 = - 3[/tex]

Therefore the equation is
[tex]x = - 3[/tex]

The correct answer is A.

or you could have also obtained the equation as follows using any of the points.

[tex]y - 7 = \frac{7}{0} (x + 3)[/tex]

This implies that,

[tex]0(y - 7) = 7(x + 3)[/tex]

[tex]0 = 7(x + 3)[/tex]

We divide through by 7 to get,
[tex]0 = x + 3[/tex]

hence
[tex]x = - 3[/tex]