Answer:
The volume of NaOH required to make 0.4 L of 0.1 M solution is 2.09 ml.
Explanation:
Let us assume the 50% of the solution to be by volume.
Molarity of solution = 0.1 M
O.1 M solution means, 0.1 moles of solute in 1L of solution.
Moles of NaOH in 0.4 L solution = 0.1 [tex]\times[/tex] 0.4
Moles of NaOH = 0.04
Density = [tex]\rm \frac{mass}{volume}[/tex]
Mass of 1 ml of 50% NaOH solution = [tex]\rm Density\;\times\;Volume\;\times\;Dilution[/tex]
Mass of 1 ml 50% NaOH solution = 1.525 [tex]\times[/tex] 1 [tex]\times\;\frac{50}{100}[/tex]
Mass of 1 ml of 50% NaOH solution = 0.7625 g
Moles of NaOH in 1 ml of 50% NaOH solution = [tex]\rm \frac{0.7625}{40}[/tex]
Moles of NaOH in 1ml of 50% NaOH solution = 0.01906 moles/liters
Molarity = [tex]\rm moles\;\times\;\frac{1000}{volume (ml)}[/tex]
Volume = [tex]\rm moles\;\times\;\frac{1000}{Molarity}[/tex]
Volume of NaOH = [tex]\rm 0.01906\;\times\;\frac{1000}{0.1}[/tex] ml
Volume of NaOH = 2.09 ml
The volume of NaOH required to make 0.4 L of 0.1 M solution is 2.09 ml.
For more information, refer the link:
https://brainly.com/question/8732513?referrer=searchResults
