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To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed of 0.4 m/s relative to the bus. What is the velocity of the man according to a stationary observer?

Respuesta :

9.6m/s - apex .........................

Answer:

v = 9.6 m/s

Explanation:

Here we know that velocity is bus is

[tex]v = 10 m/s[/tex]

also the person inside the bus is moving in opposite direction with repect to bus at speed of 0.4 m/s

now we know that

[tex]\vec v_{12} = \vec v_1 - \vec v_2[/tex]

now we know that

[tex]\vec v_{12} = -0.4 m/s[/tex]

[tex]v_1 = ?[/tex]

[tex]v_2 = 10 m/s[/tex]

now we have

[tex]-0.4 = v_1 - 10[/tex]

[tex]v_1 = 9.6 m/s[/tex]

so velocity of man is 9.6 m/s in direction of bus with respect to stationary observer

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