What is the total number of atoms contained in 80. grams of neon?
A) 6.0 x 10^23 B) 1.2 x 10^24
C) 2.4 x 10^24 D) 4.8 x 10^24

The answer is C) ,but I have no idea why.......
PLEASE HELP!!!!!!!!!!!!!!!

Respuesta :

Neon has a molar mass  of 20.18 g/mol so the number of moles is:

moles Ne = 80 / 20.18

moles Ne = 3.96 mol

 

We know that the Avogadros number is 6.022 x 10^23 atoms / mol so:

atoms Ne = 3.96 mol * 6.022 x 10^23 atoms / mol

atoms Ne = 2.4 x 10^24

 

So the answer is C

The total number of atoms in the 80 grams of Neon gas are 2.4 [tex]\rm \times\;10^2^4[/tex] .

The number of atoms present in 1 mole of an element is given by the Avogadro number.

Since the weight of Neon gas is 80 grams. The moles of Ne gas are:

[tex]\rm Moles\;=\;\dfrac{weight}{molecular\;weight}[/tex]

molecular weight of Ne = 20.18 g/mole.

Moles of Ne = [tex]\rm \dfrac{80\;g}{20.18\;g/mole}[/tex]

Moles of Ne = 3.96 moles.

1 mole of Ne = [tex]\rm 6.023\;\times\;10^2^3[/tex] atoms.

3.96 moles of Ne = 3.96 [tex]\rm \times\;6.023\;\times\;10^2^3[/tex] atoms

Atoms of Ne = 2.4 [tex]\rm \times\;10^2^4[/tex].

The total number of atoms in the 80 grams of Neon gas are 2.4 [tex]\rm \times\;10^2^4[/tex] .

For more information, refer to the link:

https://brainly.com/question/14190064