We integrate the given equation such that,
integral of g(x) = (5/3)x³ - 9x² + 35x
Substituting,
x = 13
integral of g(x) = (5/3)(13³) - 9(13)² + 35(13)
= 2595.67
and, x = 0
integral of g(x) = 0
The area is 2595.67 - 0 = 2595.67
For the second part,
x = 1
integral of g(x) = (5/3)(1)³ - 9(1)² + 35(1)
= 27.67
Area under the curve between x = 0 and x = 1 is 27.67
The difference between the two areas is,
2595.67 - 27.67 = 2568.0
Answer: 2568.0 units squared
