A small pickup truck that has a camper shell slowly coasts toward a red light with negligible friction. two dogs in the back of the truck are moving and making various inelastic collisions with each other and the walls. what is the effect of the dogs on the motion of the center of mass of the system (truck plus entire load)? what is their effect on the motion of the truck?

Respuesta :

It's increasing the velocity of the pickup truck because it is rocking back and forth hitting each other and the truck. The truck can only be slowed down by the weight of the dogs.

The effect of motion of the two dogs on the movement of the truck and on the center of mass of the system is that; they will have no effect on the motion of the truck and center of mass of the system.

  • We want to find the effect of motion of the two dogs on the movement of the truck and on the center of mass of the system.

  • Now, the formula for center of mass of this system is;

x_cm = (m₁x₁ + m₂x₂ + m₃x₃)/(m₁ + m₂ + m₃)

Where;

m₁ is mass of first dog

x₁ is distance of first dog

m₂ is mass of second dog

x₂ is distance of second dog

m₃ is mass of truck

x₃ is distance of truck

  • Now, the combined mass of both dogs can't be more than that of the truck and as such the movement of the dogs will have no effect on the motion of the truck and its' center of gravity.

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