In his piggy bank, Neil has three times as many dimes as nickels and he has four more quarters than nickels. The coins total are 4.60. How many of each coin does he have?

Set it up as an equation
d = dimes
n = nickles
q = quarters

3 times as many dimes as nickles:
d = 3n

4 more quaters than nickles:
n = q - 4

The total value of the coins are
4.60 = 0.10*d + 0.05*n + 0.25*q

You should be able to use these equations to solve the problem

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cristoshiwa cristoshiwa · Answer 2 · 2020-04-24T03:30:13+02:00

Answer: Neil has 10 quarters, 6 nickels and 18 dimes.

Step-by-step explanation: Suppose the quantity of dimes Neil has is represented by D, the quantity of nickels is N and of quarters is Q.

Neil has three times as many dimes as nickels, so:

D = 3N (1)

Four more quarters than nickels, so:

N = Q - 4 (2)

And the sum of the valor the coins is 4.6:

0.1D + 0.05N + 0.25Q = 4.6 (3)

To solve it, substitute (2) in (1):

D = 3(Q - 4)

D = 3Q - 12 (4)

Now, using (2) and (4), substitute in (3):

0.1(3Q - 12) + 0.05(Q - 4) + 0.25Q = 4.6

0.3Q + 0.05Q + 0.25Q = 4.6 + 1.2 + 0.2

0.6Q = 6

Q = 10

With Q, find N:

N = 10 - 4

N = 6

With N:

D = 3.6

D = 18

Neil has 10 quarters, 6 nickels and 18 dimes.