In labrador retrievers, black coat (b) is dominant to brown coat (b) and normal vision (n) is dominant to blindness (n). the genes for coat color and blindness are on separate chromosomes. you cross a dog that is heterozygous for coat color and vision with a blind brown dog. which statements are true about this scenario? check all that apply.

Question

11-11-2017
Biology

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In labrador retrievers, black coat (b) is dominant to brown coat (b) and normal vision (n) is dominant to blindness (n). the genes for coat color and blindness are on separate chromosomes. you cross a dog that is heterozygous for coat color and vision with a blind brown dog. which statements are true about this scenario? check all that apply.

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Please help me understand this..

underV underV · Answer 1 · 2017-11-21T13:04:48+01:00

Black coat allele: B
brown coat allele: b
normal vision: N
blindness: n

A dog that is heterozygous for coat color means it is Bb, and he is heterozygous for the vision trait so, Nn. This dog is black and can see.
The other dog that is blind and brown, means he has the genotype: bbnn
Cross: BbNn x bbnn
The genotypes of the offspring:
BbNn - 1/4 black and normal
Bbnn - 1/4 black and blind
bbNn - 1/4 brown and normal
bbnn - 1/4 brown and blind
with this information and the punnet square attached you can choose the correct statements.