A chemist has one solution that is 60%alcohol and another that is 35%alcohol how much of each must she use to make 15 liters of a solution that is 50%alcohol
Let n be the amount of 60% solution; 15-n be the amount of 35%. Then: .6n+.35(15-n)=.5(15) .25n+5.25=7.5 n=9 15-n=6 9 liters of 60% solution;6 liters of 35% solution ☺☺☺☺
