From triangle midsegment theorem we know, that a midsegment connecting two sides of a triangle is parallel to the third side and is half as long, so:
1.
Midsegment length = 6x+4
Third side length = 4x+56
and
[tex]4x+56=2\cdot(6x+4)\\\\4x+56=12x+8\quad|-4x\\\\4x+56-4x=12x+8-4x\\\\56=8x+8\quad|-8\\\\56-8=8x+8-8\\\\48=8x\quad|:8\\\\\boxed{x=6}[/tex]
so midsegment length:
[tex]L=6x+4=6\cdot(6)+4=36+4=\boxed{40}[/tex]
Answer C.
2.
The tree is a midsegment so it is half as high as a building:
[tex]\text{Tree } =120:2=\boxed{60\,\text{ft}}[/tex]
Answer A.
