Answer:
Inverse variation states:
If y varies inversely as x i.,e
[tex]y \propto \frac{1}{x}[/tex]
then the equation is in the form of:
[tex]y = \frac{k}{x}[/tex]......[1] , where k is the constant of variation
As per the statement:
y is 1.5 when x is 8
Solve for k:
Substitute the given value in [1] we have;
[tex]1.5 = \frac{k}{8}[/tex]
Multiply both sides by 8 we have;
12 = k
or
k = 12
Then, the equation become:
[tex]y = \frac{12}{x}[/tex]
We have to find y when x is 2.
then;
[tex]y = \frac{12}{2}[/tex]
Simplify:
y = 6
Therefore, the value of y is, 6
