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1.) Solve 2x^2-12x+20=0 using the quadratic solution set? What is the solution set?

a.) {3+I, 3-i}
b.) {3+2i, 3-i}
c.) {2i, -3i}
d.) {-3+i, -3-i}

2.) Lucy divided the two polynomials shown. 3x+2 sqrt 3x^2-x-2

a.)x+1
b.)x-2+3/3x+2
c.) x-1
d.) x-2+-3/3x+2

Respuesta :

altavistard
Please, share just ONE problem at a time.  Thanks.

Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2:  x^2 - 6x + 10 = 0

Identify a, b and c:  a=1, b=-6 and c=10.  Then b^2=36.

Write out the solutions using the quadratic formula:

        6 plus or minus sqrt(36-40)
x = ---------------------------------------
                            2

sqrt(36-40) = sqrt(-4) = plus or minus i2

Then:
 
         6 plus or minus i2
x = --------------------------- (answer)
                  2

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