A boy throws a ball up into the air with a speed of 8.2 m/s. the ball has a mass of 0.3 kg. How much gravitational potential energy will the ball have at the top of its flight?

Respuesta :

gpe=ke so 0.5mv^2 0.5*0.3*8.2^2=10.086

Answer:

Gravitational potential energy, PE = 10.08 J

Explanation:

It is given that,

Speed with which the ball is thrown, v = 8.2 m/s

Mass of the ball, m = 0.3 kg

We need to find the gravitational potential energy of the ball when it is at the top of flight. The ball is thrown up into the air.

As per law of conservation of energy, the kinetic energy at the top is converted to gravitational potential energy as :

[tex]PE=KE=\dfrac{1}{2}mv^2[/tex]

[tex]PE=\dfrac{1}{2}\times 0.3\times 8.2^2[/tex]

PE = 10.08 J

So, the gravitational potential energy at the top of the flight is 10.08 Joules. Hence, this is the required solution.