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Find the solution of the differential equation (6−8xy2)dy/dx=y3 such that x=2 when y=4 by regarding y as the independent variable rather than x.

Respuesta :

ejelonubenedict
dy/dx = y³/(6-8xy²)
buy x is the dependent variable
so
dx/dy= (6-8xy²)/y³ = (6-8×2×16)/4³
dx/dy = -250/ 64 = -125/32

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