Answer:
a=5.20 m/s²
Explanation:
Given Data
Thrust = T (N)=3.0×10⁵N
Mass=m=20000kg
To find
acceleration=a=?
Solution
Newton Second law states that
The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
(resultant force F)=ma
a=(resultant force F)/m
where
(resultant force F) is (Thrust-weight)
Weight = mg = 2.0^4 kg*9.8 N/kg = 1.96^5 N
a = (resultant force F) / mass
a = (T - mg)/m = (3.0^5 N - 1.96^5 N)/ 2.0^4 kg
a=5.20 m/s²
The rocket's initial upward acceleration is 5.2m/s²
According to Newton's second law of motion
[tex]\sum F = ma[/tex]
The sum of forces is the difference between the weight and the thrust
[tex]\sum F = T -W[/tex]
[tex]T - W = ma\\a=\frac{T-W}{a}[/tex]
Given the following parameters:
T = [tex]3.0 \times 10^5 N[/tex]
W = [tex]20,000 \times 9.8 = 1.96 \times 10^5 N[/tex]
m = [tex]20,000kg[/tex]
Substitute the given parameters into the formula to have:
[tex]a=\frac{(3.0-1.96)\times 10^5}{2\times 10^4} \\a=\frac{1.04\times 10^5}{2\times 10^4} \\a = 0.52 \tmes 10\\a = 5.2m/s^2[/tex]
Hence the rocket's initial upward acceleration is 5.2m/s²
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