The equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10 is y = (-2/5)x - 2
The equation of a straight line is given by:
y = mx + b
where y, x are variables, m is the slope of the line and b is the y intercept.
The slope of the line 2x + 5y = 10 is:
2x + 5y = 10
5y = -2x + 10
y = -2/5x + 10
Hence the slope of the line 2x + 5y = 10 is -2/5
Since both lines are parallel, hence the slope of the other line is the same (-2/5). Hence the equation of the line is:
[tex]y-y_1=m(x-x_1)\\\\y-(-4)=-\frac{2}{5} (x-5)\\\\y+4=-\frac{2}{5} x+2\\\\y=-\frac{2}{5} x-2[/tex]
The equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10 is y = (-2/5)x - 2
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