Answer:
The leftmost 4 has a positional value of [tex]4\times10 ^ 3[/tex]. While the other 4 that appears in the displayed figure has a positional value of [tex]4\times10^2[/tex]. Then, it can be said that the relationship between the major and the minor is: [tex]\frac{4\times10 ^ 3}{4\times10 ^ 2} = 10[/tex]. That is, the relationship is that the 4 on the left is 10 times greater than the other 4 .
Step-by-step explanation:
