Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad \begin{array}{lllll} center\ (&{{ h}},&{{ k}})\qquad radius=&{{ r}}\\ &3&5&2 \end{array} \\\\\\ (x-3)^2+(y-5)^2=2^2\implies (x-3)^2+(y-5)^2=4[/tex]