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Geraldine is picking a four-digit password by using the digits 0 through 9. She can use each digit only once. How many different passwords are possible?

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musiclover10045

0-9 = 10 numbers

 1st digit can be 1 0f 10

2nd digit can be 1 of 9

3rd digit can be 1 of 8

4th digit can be 1 of 7



10 * 9 *8*7 = 5040 different combinations

MrRoyal

The number of different possible passwords are possible

Given that each digit can be used once, then:

  • The first digit can be any of the 10 digits
  • The second digit can be any of the remaining 9 digits
  • The third digit can be any of the remaining 8 digits
  • The fourth digit can be any of the remaining 7 digits

So, the number of passwords is:

n = 10 * 9 * 8 * 7

Evaluate the products

n = 5040

Hence, there are 5040 different possible passwords

Read more about permutation and combination at:

https://brainly.com/question/11732255

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