Answer:
The correct answer is oxidation-reduction.
Explanation:
This reduction-oxidation reaction is given by the following semi-reactions:
[tex]Br_{2}[/tex] + 2 [tex]e^{-}[/tex] → 2 [tex]Br^{-1}[/tex] (reduction)
2 [tex]K^{0}[/tex] - 2 [tex]e^{-}[/tex] → 2 [tex]K^{1}[/tex] (oxidation)
[tex]Br_{2}[/tex] is an oxidation agent, K is a reducing agent.
This means that [tex]Br_{2}[/tex] oxidizes K by increasing its oxidation number from 0 to 1.
[tex]Br_{2}[/tex] is reduced, decreasing its oxidation number from 0 to -1.
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