What is the concentration of nitrate ions in a 0.125 M Mg(NO3)2 solution

The dissociation of Mg(NO₃)₂ can be expressed as follow,

Mg(NO₃)₂ --> Mg²⁺ + 2NO₃⁻

Each mole of the Mg(NO₃)₂ will dissociate into 2 moles of NO₃⁻. Thus, to determine the concentration of the nitrate ions, we multiply the given value of two.
M = (0.125M)(2) = 0.250M

ANSWER: 0.250 M

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okpalawalter8 okpalawalter8 · Answer 2 · 2022-02-21T13:40:01+01:00

We have that the concentration of the nitrate ions is mathematically given as

M= 0.250M

The concentration of the nitrate ions

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Generally the equation for the Reaction is mathematically given as

Mg(NO₃)₂ --> Mg²⁺ + 2NO₃⁻

Each mole of the Mg(NO₃)₂ will dissociate into 2 moles of NO₃⁻.

the concentration of the nitrate ions is

M = (0.125M)(2)

M= 0.250M

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