It means you want to find the point along the line GK that divides the length of the line into a 2/3 ratio.
[tex]\frac{GP}{PK} = \frac{2}{3} [/tex]
GK = GP+PK = 2+3 = 5
In this way, we can think of the line as being in 5 equal parts, 2 parts consist of GP, and 3 parts for PK.
Now find the horizontal and vertical distances from point g to k.
H: 8 - 1 = 7
V: 12 - 2 = 10
Divide by 5
H: 7/5
V: 10/5 = 2
Adding these to point 'g' will get you to some point that is 1/5 the length of GK.
But point 'p' must be 2 parts away from 'g'.
Multiply by 2
H: 7/5*2 = 14/5
V: 2*2 = 4
Add to 'g'
p = (1+14/5, 2 +4)
[tex]p = (\frac{19}{5}, 6)[/tex]
