contestada

I NEED HELP SOOOO MUCH IM SOOO LOST I WILL GIVE A BRAINLIEST TO THE PERSON WHO INCLUDES ALL WORK, CORRECT ANSWER,AND EVERYTHING MAKES SENSE.

(Variables on both sides of an equation)
Solve: 5(a-1)-15=3(a+2)+4

Respuesta :

5(a-1) - 15 = 3(a+2) + 4
Open all parenthesis and distribute
5a - 5 - 15 = 3a + 6 + 4
Simplify
5a - 20 = 3a + 10
Add both sides by 20 and subtract both sides by 3a
2a = 30
a = 15
highwireact
We start by using the distributive property to expand the terms [tex]5(a-1)[/tex] and [tex]3(a+2)[/tex]. When we do, we obtain [tex]5a-5[/tex] and [tex]3a+6[/tex].

Putting those back into our equation, we have:

[tex]5a-5-15=3a+6+4[/tex]

Next, we combine all of the constants on either side:

[tex]5a-20=3a+10[/tex]

Finally, we want to get the variable a by itself on one side of the equation, so we perform the following steps to isolate it:

[tex]5a=3a+30[/tex] (Add 20 to both sides)
[tex]2a=30[/tex] (Subtract 3a from both sides)
[tex]a=30/2=15[/tex] (Divide both sides by 2 to isolate a)

So, we obtain our answer of [tex]a=15[/tex].

Otras preguntas