Respuesta :
If there is a multiple choice then the answer would be 0.029. I hope this helps you
Answer:
There are 0.0292 moles of sucrose available for this reaction
Explanation:
Number of moles of a compound = [tex]\frac{mass of compound}{molar mass of the compound}[/tex]
Here mass of sucrose is 10.0 g. Molar mass of sucrose is 342.3 g/mol
So moles of sucrose available for this reaction = [tex]\frac{10 g}{342.3 g/mol}= 0.0292 moles[/tex]