The volume of NaOH needed for the titration is calculated by equating the number of moles of KHP and NAOH.
(1) number of moles of KHP:
n = mass of KHP / molar mass of KHP
Substituting,
n = 0.061 g / (204.22 g/mol) = 2.987 x 10⁻⁴ moles KHP
(2) number of moles of NaOH
n = (volume NaOH in L)(molarity of NaOH)
n = V x 0.01
Equating,
0.01V = 2.987 x 10⁻⁴
The value of V from the equation is 0.0299L of NaOH.
Converting the value to mL will give us the answer of 29.87 mL.
