moles AgCl = moles Cl- = 0.02290 L x 0.1000 M = 0.002290
let x = mass NaCl ( molar mass = 58.44 g/mol)
let y = mass KCl ( molar mass =74.55 g/mol)
x + y = 0.1586
x / 58.44 + y / 74.55 = 0.002290
74.55 x + 58.44 y=9.98
74.55 ( 0.1586 - y) + 58.44 y = 9.98
11.8 - 74.55 y + 58.44 y = 9.98
1.82 = 16.11 y
y = 0.113 g
% KCl = 0.113 x 100/0.1586=71.2