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A daredevil decides to jump a canyon of width 8.88 m. to do so, he drives a motorcycle up an incline sloped at an angle of 22.5 ◦ . the acceleration of gravity is 9.8 m/s 2 . what minimum speed must he have in order to clear the canyon? answer in units of m/s.

Respuesta :

Kalahira
What we need first is the formula to calculate maximum horizontal distance. It is: R = v^2(Sin 2A)/g where R is range, v is velocity, A is angle, and g is the gravity constant. we know that R=8.88 meters, A= 22.5 degrees, and g= 9.8 m/s^2 What we are looking for is v=?. We need to solve the equation for v. That gives us: v =((R*g)/(Sin(2* 22.5)))**1/2 Next, all we have to do is plugin the values. v = ((8.88m * 9.8 m/s**2)/(sin(2*22.5 degrees))**1/2 All this give us v = 10.11 m/s