Answer:
[tex]a_c = 3.92 m/s^2[/tex]
Explanation:
tangential speed of the girl is given as
[tex]v_t = 2.8 m/s[/tex]
diameter of the circle is given as
[tex]d = 4.0 m[/tex]
so here the radius of the circle is given as
[tex]R = 2.0 m[/tex]
now we know that centripetal acceleration of the object moving in circle is given as
[tex]a_c = \frac{v^2}{R}[/tex]
[tex]a_c = \frac{2.8^2}{2}[/tex]
[tex]a_c = 3.92 m/s^2[/tex]
