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Raphael graphed the functions g(x) = x + 2 and f(x) = x – 1. How many units below the y-intercept of g(x) is the y-intercept of f(x)? The y-intercept of f(x) is units below the y-intercept of g(x).Raphael graphed the functions g(x) = x + 2 and f(x) = x – 1. How many units below the y-intercept of g(x) is the y-intercept of f(x)? The y-intercept of f(x) is units below the y-intercept of g(

Respuesta :

For the first question, the y-intercept of f(x) is 3 units below the y-intercept of g(x). For the second question, the y-intercept of f(x) is 3 units above the y-intercept of g(x).

Answer:

The y-intercept of f(x) is 3 units below the y-intercept of g(x).

Step-by-step explanation:

We are given,

The functions [tex]f(x)=x-1[/tex] and [tex]g(x)=x+2[/tex].

Now, y-intercept is the point where the graph of the function crosses y-axis.

So, y-intercept is obtained when x= 0.

Substituting x= 0 in the functions, we get,

[tex]f(0)=0-1\\f(0)=-1[/tex] and [tex]g(0)=0+2\\g(0)=2[/tex].

Thus, we get that,

The y-intercept of the the function f(x) is -1.

The y-intercept of the function g(x) is at 2.

Thus, the y-intercept of f(x) is 2-(-1)= 3 units below the y-intercept of g(x) as seen below.

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