Respuesta :

xmoles (6.022x10^(23)) = number of atoms of water at STP 
I belive thats correct ^,^

Answer:Total atoms in 131.97 liters of water vapor at STP are[tex]1.0643\times 10^{25} atoms[/tex].

Explanation:

At STP, one mole of gas occupies 22.4 L of volume.

Then 131.97 L of the volume will be occupied by:

[tex]\frac{1}{22.4 L}\times 131.97 L=5.8915 moles[/tex]

Number of water vapor molecules :

[tex]Moles\times N_A=5.8915 mol\times 6.022\times 10^{23} mol^{-1}=3.5478\times 10^{24} molecules[/tex]

In 1 molecule of water vapor = 3 atoms

Total number of atoms in [tex]3.5478\times 10^{24} molecules[/tex]:

[tex]3\times 3.5478\times 10^{24} molecules=1.0643\times 10^{25} atoms[/tex]

Total atoms in 131.97 liters of water vapor at STP are[tex]1.0643\times 10^{25} atoms[/tex].