Answer:
[tex]x=\pm2[/tex]
Step-by-step explanation:
The given equation is
[tex]x^2-14=-10[/tex]
Add 14 to both sides of the equation.
[tex]x^2=-10+14\\\\x^2=4[/tex]
Now, take square root both sides. Whenever, we take square root both sides, we include plus minus sign
[tex]\sqrt{x^2}=\pm\sqrt{4}[/tex]
On simplifying, we get
[tex]x=\pm2[/tex]
