Point slope form of a line:
[tex]y-y_1=m(x-x_1)[/tex] where [tex]m[/tex] is your slope and [tex](x_1,\ y_1)[/tex] is a point on your line.
For a line with a slope of 3/5 that passes through (10, -2)...
[tex]m=\frac35,\ x_1=10,\ y_1=-2[/tex]
Let's plug these values into our formula.
[tex]y-(-2)=\frac35(x-10)[/tex]
Subtracting by a negative is the same thing as adding (the double negatives cancel), so let's simplify that.
[tex]\boxed{y+2=\frac35(x-10)}[/tex]
There's our equation in point-slope form. (keep in mind that you're not going to want to distribute that 3/5 or subtract the 2 or anything. You want to keep it similar to the formula.
