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What are the exact solutions of x2 - 3x - 5 = 0? x = the quantity of negative 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 29 all over 2 x = the quantity of 3 plus or minus the square root of 11 all over 2 x = the quantity of negative 3 plus or minus the square root of 11 all over 2

Respuesta :

Answer:

[tex]x= \frac{3+-\sqrt{29}}{2}[/tex]

Step-by-step explanation:

x^2 - 3 x -5=0

To solve for x we apply quadratic formula

[tex]x= \frac{-b+-\sqrt{b^2-4ac}}{2a}[/tex]

From the given equation

a=1 , b=-3  and c=-5

Plug in all the values in the formula

[tex]x= \frac{3+-\sqrt{(-3)^2-4(1)(-5)}}{2(1)}[/tex]

[tex]x= \frac{3+-\sqrt{29}}{2}[/tex]

We cannot simplify square root (29)

So we keep as it is

[tex]x= \frac{3+-\sqrt{29}}{2}[/tex]

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