Lana is the oldest of four sisters. Her youngest sister is half her age. The other two sisters are twins 2 years younger than Lana. When the four sisters' ages are added together, the result is 45. If the youngest sister is n years old, what is n? will give meadel

Respuesta :

Therefore, the ages of Lana, her youngest sister and her twin sisters are 14, 7 and 12 respectively.

Algebra

Let

  • Lana's age = x
  • Lana's youngest sister's birthday age = 1/2x
  • Her twin two sisters = x - 2
  • Total ages = 45

x + 1/2x + (x - 2) + (x - 2) = 45

x + 1/2x + x - 2 + x - 2 = 45

3 1/2x = 45 + 2 + 2

3 1/2x = 49

x = 49 ÷ 3 1/2

= 49 ÷ 7/2

= 49 × 2/7

x = 14

Therefore,

Lana's age = x

= 14 years

Lana's youngest sister's birthday age = 1/2x

1/2 × 14

= 7 years

Her twin two sisters = 2(x - 2)

= 2(14 - 2)

= 2(12)

= 24 years

That is, 12 years each

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