Respuesta :
We have a system here, letting C = Claire's age and D = David's age,
[tex] \left \{ {{C=2D} \atop {C+D=9}} \right. [/tex]
Substituting C=2D into the 2nd equation,
C+D = 9
2D+D = 9
D = 3
Substituting D=3 back into the first equation,
C=2D
C=2*3
C=6
Therefore Claire is 6 and David is 3.
Hope that helped!
~Cam943
[tex] \left \{ {{C=2D} \atop {C+D=9}} \right. [/tex]
Substituting C=2D into the 2nd equation,
C+D = 9
2D+D = 9
D = 3
Substituting D=3 back into the first equation,
C=2D
C=2*3
C=6
Therefore Claire is 6 and David is 3.
Hope that helped!
~Cam943
So,
Let c represent Claire's age and d represent David's age.
c = 2d
c + d = 9
Substitute 2d for c in the second equation.
2d + d = 9
Collect Like Terms.
3d = 9
Divide both sides by 3.
d = 3
Substitute 3 for d in the first equation.
c = 2(3)
c = 6
Claire is 6 years old and David is 3 years old.
Let c represent Claire's age and d represent David's age.
c = 2d
c + d = 9
Substitute 2d for c in the second equation.
2d + d = 9
Collect Like Terms.
3d = 9
Divide both sides by 3.
d = 3
Substitute 3 for d in the first equation.
c = 2(3)
c = 6
Claire is 6 years old and David is 3 years old.