Respuesta :
Answer: Order will be F,D,C and Fourth Option is correct and x = 10
Step-by-step explanation:
Since we have given that
[tex]\sqrt{6x+4}=8[/tex]
We first transpose the square root to the right , so it becomes square of 8,i.e.
[tex]6x+4=8^2\\\\6x+4=64[/tex]
Now, transpose 4 to the right so it will get subtract from 64 i.e.
[tex]6x=64-4\\\\6x=60[/tex]
Since 6 is multiplied to x on tranposing it will get divided by 60 i.e.
[tex]x=\frac{60}{6}\\\\x=10[/tex]
Hence, on simplification, we get x=10.
Hence , the order is F,D,C.
The correct steps to follow in other to solve the equation is F the D then C
Given the equation : [tex]\sqrt{6x + 4} = 8[/tex]
STEP 1 :
Take the square of both sides (F)
[tex](\sqrt{6x + 4})^{2} = 8^{2} \\6x + 4 = 64[/tex]
STEP 2 :
Subtract 4 from both sides (D)
[tex]6x + 4 - 4 = 64 - 4\\6x = 60[/tex]
STEP 3 :
Divide both sides by 6 (C)
[tex]\frac{6x}{6} = \frac{60}{6}\\x = 10[/tex]
Hence, the correct steps to follow are : F then D then C
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