A boy has 11 coins in dimes and quarters. Their value is $1.70. How many of each does he have? Which of the following equations could be used to solve the problem?

Respuesta :

x - number of dimes, y - number of quarters
x + y = 11
0.10 x + 0.25 y = 1.70
0.10 x + 0.25 ( 11 - x ) = 1.70
you can solve it:
0.10 x + 2.75 x - 0.25 x  = 1.70
0.15 x = 1.05
x = 1.05 : 0.15         
x = 7  ( a boy has 7 dimes and 4 quarters )
Answer: 0.10 x + 0.25 ( 11 - x ) = 1.70
0.25x + 0.10(11-x) = 1.70 ←←←←←←←←←(This is the answer to your question)
25x + 10(11-x) = 170
25x + 110 - 10x = 170
15x + 110 = 170
15x = 60
x = 4
11-4 = 7
4=quarters
7=dimes
To answer your question:

0.10 x + 0.25 ( 11 - x ) = 1.70

I hope this helps you!
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