a biased coin is flipped the probability of getting heads is 80% a player wins 2$ each time he gets tails and a game involves 10 tosses what is the expected value of the money earned in a game?

Respuesta :

80% of 10 tosses is 8 tosses so it will be heads 8 times, and tails 2 times. meaning they will get 4$

Answer: The expected value is $4.

Step-by-step explanation:

We have that the probability of winning is equal to 20% (or 0.20 in decimal form)

The expected value can ve calculated as:

Ev = (p₁x₁ + p₂x₂ + .... + pₙxₙ)

Where x stands for a given event, and p for the probability of the event.

Here we have:

x₁ = winning $2

p₁ = 0.20

x₂= not winning anithinh.

p₂ = 0.80

Then for each flip the expected value is:

Ev = 0.2*$2 + 0.8*$0 = 0.2*$2

and in 10 flips, we have 10 times that amount:

Total expected value = 10*0.2*$2 = 2*$2 = $4