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If the laser is pointed toward a pinhole with a diameter of 1.2 mm , how many photons will travel through the pinhole per second? assume that the light intensity is equally distributed throughout the entire cross-sectional area of the beam. (1 w = 1 j/s)

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shinmin

Plug in the information they give you into the equation E = hc/wavelength 


E= (hc)/532x 10^-9 
E = 3.74 x10 ^-19 Joules 



Now take the data for 5 J/s and divide it by the 3.74 x10 ^-19 Joules to get 1.34 x 10 ^ 19 photons/second. 


Then, look for the area of the circle.


Area of a circle is (pi)(r^2) so the ratio will be: 



[(pi (.6^2) ]/ [ (pi) (2.75^2) ] 



Note that since the pi will cancel it'll just be (.6^2)/(2.75^2) and the values .6 and 2.75 are found by dividing the diameters you are given by 2, since this is of course the radius. 



Then multiply (.6^2)/(2.75^2) by 1.34 x 10 ^ 19 photons/second to get 6.39 x 10^17 photons/second.

adefioyelaoye

The number of photons which will travel through the pinhole per second is 6.39 x 10¹⁷ photons/second.

What is Photon?

This can be defined as the smallest discrete amount or quantum of electromagnetic radiation.

E = hc/wavelength

E= (hc)/532x 10⁻¹⁹

E = 3.74 x10⁻¹⁹ Joules

From data we can deuce that 5 J/s /3..74 x10⁻¹⁹ Joules = 1.34 x  10¹⁹photons/second.

Multiply (6²)/(2.75²) by 1.34 x 10¹⁹ photons/second = 6.39 x 10^17 photons/second.

Read more about Photons here https://brainly.com/question/1844674

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