How many ammonium ions and how many sulfate ions are present in an 0.400 mol sample of (NH4)2SO4? How many atoms of N, H, S, and O are contained in this sample?

Respuesta :

In every 1 mole of (NH₄)₂SO₄, there are 2 moles of ammonium (NH₄) ions and 1 mole of sulfate (SO₄) ions. Also, in every 1 mole of (NH₄)₂SO₄, there are 2 moles of N, 8 moles of H, 1 mole of S and 4 moles of O. Then, we use the Avogadro's number, 6.022×10²³ particles/mol, to find the number of ions and atoms.

1. Number of ammonium ions
0.4 mol(2 mol NH₄/1 mol (NH₄)₂SO₄)(6.022×10²³ ions/mol) = 4.82×10²³ ammonium ions

2. Number of sulfate ions
0.4 mol(1 mol SO₄/1 mol (NH₄)₂SO₄)(6.022×10²³ ions/mol) = 2.41×10²³ sulfate ions

3. Atoms of N
0.4 mol(2 mol N/1 mol (NH₄)₂SO₄)(6.022×10²³ atoms/mol) =4.82×10²³ nitrogen atoms

4. Atoms of H
0.4 mol(8 mol H/1 mol (NH₄)₂SO₄)(6.022×10²³ atoms/mol) =1.927×10²⁴ hydrogen atoms

5. Atoms of S
0.4 mol(1 mol S/1 mol (NH₄)₂SO₄)(6.022×10²³ atoms/mol) =2.41×10²³ sulfur atoms

6. Atoms of O
0.4 mol(4 mol O/1 mol (NH₄)₂SO₄)(6.022×10²³ atoms/mol) =9.635×10²³ oxygen atoms

Taking into account the Avogadro's Number:

  • 2.41×10²³ sulfate ions are present in an 0.400 mol sample of (NH₄)₂SO₄.
  • 4.82×10²³ nitrogen atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.
  • 1.93×10²⁴ hydrogen atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.
  • 2.41×10²³  sulfur atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.
  • 9.637×10²³  oxygen atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.

The subscripts next to each atom allow you to find the number of moles of each element in the compound. Then, in every mole of (NH₄)₂SO₄ there are:

  • 2 moles of ammonium (NH₄) ions and 1 mole of sulfate (SO₄) ions.
  • 2 moles of N, 8 moles of H, 1 mole of S and 4 moles of O.

On the other side, Avogadro's Number is the number of particles that make up a substance (they can be atoms, ions or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

  • Number of sulfate ions

Then, the number of sulfate ions present in a 0.400 mole sample of (NH₄)₂SO₄ can be determined by:

[tex]0.400 moles of (NH_{4})_{2}SO_{4} x\frac{1 mole of sulfate}{1mole of (NH_{4})_{2}SO_{4} } x\frac{6.023x10^{23}ions }{1 mole of sulfate} =[/tex]2.41×10²³ sulfate ions.

2.41×10²³ sulfate ions are present in an 0.400 mol sample of (NH₄)₂SO₄.

  • Number of N atoms

The number of N present in a 0.400 mole sample of (NH₄)₂SO₄ can be determined by:

[tex]0.400 moles of (NH_{4})_{2}SO_{4} x\frac{2 mole of N}{1mole of (NH_{4})_{2}SO_{4} } x\frac{6.023x10^{23}ions }{1 mole of N} =[/tex]4.82×10²³ nitrogen atoms.

4.82×10²³ nitrogen atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.

  • Number of H atoms

The number of H present in a 0.400 mole sample of (NH₄)₂SO₄ can be determined by:

[tex]0.400 moles of (NH_{4})_{2}SO_{4} x\frac{8 mole of H}{1mole of (NH_{4})_{2}SO_{4} } x\frac{6.023x10^{23}ions }{1 mole of H} =[/tex]1.93×10²⁴ hydrogen atoms.

1.93×10²⁴ hydrogen atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.

  • Number of S atoms

The number of S present in a 0.400 mole sample of (NH₄)₂SO₄ can be determined by:

[tex]0.400 moles of (NH_{4})_{2}SO_{4} x\frac{1 mole of S}{1mole of (NH_{4})_{2}SO_{4} } x\frac{6.023x10^{23}ions }{1 mole of S} =[/tex]2.41×10²³  sulfur atoms.

2.41×10²³  sulfur atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.

  • Number of O atoms

Finally, the number of O present in a 0.400 mole sample of (NH₄)₂SO₄ can be determined by:

[tex]0.400 moles of (NH_{4})_{2}SO_{4} x\frac{4 mole of O}{1mole of (NH_{4})_{2}SO_{4} } x\frac{6.023x10^{23}ions }{1 mole of O} =[/tex]9.637×10²³ oxygen atoms.

9.637×10²³  oxygen atoms are present in an 0.400 mol sample of (NH₄)₂SO₄.

Learn more about Avogadro's Number:

  • brainly.com/question/11907018?referrer=searchResults
  • brainly.com/question/1445383?referrer=searchResults
  • brainly.com/question/1528951?referrer=searchResults