Answer:
x= [tex]\frac{B}{3(1 + 3y)}[/tex]
or
x = [tex]\frac{B}{(3 + 9y)}[/tex]
Step-by-step explanation:
The given equation is B = 3x + 9xy
We have to solve for x.
B = 3x + 9xy
Let's factor the above equation.
B = 3x(1 + 3y)
We need to solve for x.
So, divide both sides by (1 + 3y), we get
[tex]\frac{B}{(1+ 3y)} = \frac{3x(1+3y)}{(1 +3y)}[/tex]
[tex]\frac{B}{(1 + 3y)} = 3x[/tex]
This can be written as
[tex]3x = \frac{B}{(1 + 3y)}[/tex]
Now dividing both sides by 3, we get
x= [tex]\frac{B}{3(1 + 3y)}[/tex]
or
x = [tex]\frac{B}{(3 + 9y)}[/tex]
