Help for 20 points.Write the equation of the line that passes through (3, −2) and has a slope of 4 in point-slope form. (2 points)
 

y + 2 = 4(x − 3)

y − 3 = 4(x + 2)

x − 3 = 4(y + 2)

x + 2 = 4(y − 3)

Respuesta :

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ &({{ 3}}\quad ,&{{ -2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 4 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=4(x-3)\implies y+2=4(x-3)[/tex]