Respuesta :
let the numbers be x and (x-5)
x(x-5)=36
x^2-5x-36=0
solving the equation we get
x=9 and x= -4
now find out the integers
x(x-5)=36
x^2-5x-36=0
solving the equation we get
x=9 and x= -4
now find out the integers
1st number = x
2nd number = x-5
x*(x-5) = 36
x^2-5x =36
x^2 -5x-36 = 0
factor the polynomial:
(x-9) (x+4)
9-9 = 0, -4 +4 = 0
so x = 9 or -4
the question states a positive number
so x = 9
the 2 numbers are 9 and 4