Respuesta :
Answer: Our required equation is [tex]5p-4\times 5=\$75[/tex] and $19 is the original price for one lunch special.
Step-by-step explanation:
Let the original price for one lunch special be 'p'.
Amount off for each of 5 days = $4
Number of days = 5
Amount he pays for 5 lunch specials = $75
According to question, it becomes,
[tex]5p-4\times 5=\$75[/tex]
So, it becomes,
[tex]5p-20=75\\\\5p=75+20\\\\5p=95\\\\p=\dfrac{95}{5}=\$19[/tex]
So, original price for one lunch special is $19.
Hence, our required equation is [tex]5p-4\times 5=\$75[/tex] and $19 is the original price for one lunch special.
The original price for one lunch meal is $19
The coupon reduces the total amount he paid per meal. Darren would pay for $4 less for his meal
Coupon per lunch = $4
Total amount he paid in 5 days = $75
Amount he pays per day for his lunch = $75/5 = $15
Original price p for his lunch = amount paid per lunch + coupon
p = $15 + $4
p = $19
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