The formula we can use in this problem is:
v^2 = v0^2 + 2ad
d = v0t + 0.5at^2
where v is the final speed, v0 the initial speed = 0, a is the acceleration and d is distance, so:
v^2 = 2ad
d = 0.5at^2
Combining the two equations:
v^2 = 2a (0.5 at^2)
v = sqrt [a^2 t^2]
v = sqrt [(0.19 m/s^2)^2 * (120 s)^2]
v = 22.8 m/s
The previous answer is terrible. There's no need to complicate things like that.
v_f = v_i + at = 0 + (0.19)(120) = 22.8 m/s
Done
