Lola rode her bike for 7/10 of an hour on Saturday and 3/5 of an hour on Sunday. How much longer did she ride her bike on Saturday than Sunday?

Respuesta :

1 hr = 10/10
1/10 of an hr= 6 min
(7)(6)=42
Saturday she rode her bike for  42 min
Sunday
1 hr = 5/5
1/5 of an hr = 12 min
(3)(12)= 36
On sunday she rode her bike for 36 min
Finally
42-36= 6
She rode her bike 6 min longer on saturday than sunday

Answer:Lola ride for [tex]\frac{1}{10}[/tex] of an hour extra on Saturday as compared to Sunday


Step-by-step explanation:

Given: Lola rode her bike for [tex]\frac{7}{10}[/tex] of an hour on saturday

and for [tex]\frac{3}{5}[/tex] of an hour on sunday

Therefore difference of the two rides time

⇒[tex]\frac{7}{10}[/tex]-[tex]\frac{3}{5}[/tex]

Multiplying and dividing [tex]\frac{3}{5}  by 2[/tex]

⇒[tex]\frac{7}{10} -\frac{6}{10}[/tex]

⇒[tex]\frac{1}{10}[/tex] of an hour